Fisika SMA - Gerak Lurus (4) - GLBB, Gerak Lurus Berubah Berturan, Rumus GLBB, Soal GLBB (I)

Fisika SMA - Gerak Lurus (4) - GLBB, Gerak Lurus Berubah Berturan, Rumus GLBB, Soal GLBB (I)

TLDR;

This video explains the concept of uniformly accelerated rectilinear motion (GLBB), its differences from uniform rectilinear motion (GLB), and how to apply the GLBB equations to solve problems. It covers the definition of GLBB, its characteristics, and provides examples to illustrate how to use the GLBB formulas.

  • GLBB is motion in a straight line with constant acceleration.
  • The GLBB equations relate displacement, initial velocity, final velocity, acceleration, and time.
  • Problem-solving strategies involve identifying known variables and selecting the appropriate equation.

Introduction to GLBB [0:04]

The video introduces the concept of uniformly accelerated rectilinear motion (GLBB), distinguishing it from uniform rectilinear motion (GLB). GLBB is defined as motion along a straight path where the velocity changes uniformly over time. The key characteristic of GLBB is the constant acceleration, which means the velocity increases or decreases at a steady rate.

Understanding Uniformly Changing Velocity [0:41]

To illustrate uniformly changing velocity, the video presents an example of a particle moving with an initial velocity of 2 m/s, which increases by 2 m/s every second. This constant change in velocity indicates uniform acceleration. The change in velocity (delta V) is calculated for each one-second interval, demonstrating that it remains constant at 2 m/s.

Defining Acceleration in GLBB [2:54]

The video defines acceleration as the rate of change of velocity over time. In the illustrated example, the acceleration is calculated as 2 m/s per second, or 2 m/s². This constant acceleration is a defining characteristic of GLBB, leading to the conclusion that GLBB is motion with constant acceleration, which causes the object's velocity to change uniformly.

GLBB Equations [4:45]

The video transitions to discussing the equations used in GLBB, contrasting them with the single equation used in GLB (S = VT). In GLBB, the presence of acceleration modifies the equations. The three primary equations for GLBB are introduced:

  1. S = V₀T + (1/2)AT²
  2. Vₜ = V₀ + AT
  3. Vₜ² = V₀² + 2AS

Variable Identification in GLBB Equations [7:14]

Each variable in the GLBB equations is identified, including:

  • S: displacement (m)
  • V₀: initial velocity (m/s)
  • Vₜ: final velocity (m/s)
  • A: acceleration (m/s²)
  • T: time (s)

Understanding these variables is crucial for correctly applying the equations to solve problems.

GLBB Problem Example 1 [8:21]

The first example involves Maya riding a bicycle with an initial velocity of 5 m/s and accelerating at 1 m/s² for 5 seconds. The problem asks for the final velocity and the distance traveled. By identifying the known variables (V₀ = 5 m/s, A = 1 m/s², T = 5 s) and using the appropriate GLBB equations, the final velocity is found to be 10 m/s, and the distance traveled is 37.5 meters.

GLBB Problem Example 2 [12:41]

The second example involves a Boeing 737NG landing with an initial velocity of 252 km/h (70 m/s) and decelerating at -5 m/s² until it comes to a stop. The problem requires finding the length of the runway needed. Using the GLBB equations and the known variables (V₀ = 70 m/s, A = -5 m/s², Vₜ = 0 m/s), the required runway length is calculated to be 490 meters.

GLBB Problem Example 3 [16:21]

The third example features Najib riding a motorcycle from rest (V₀ = 0 m/s) and accelerating until he covers 400 meters, at which point his speedometer reads 72 km/h (20 m/s). The problem asks for the acceleration and the time taken to reach this distance. By using the GLBB equations, the acceleration is found to be 0.5 m/s², and the time taken is 40 seconds.

GLBB Problem Example 4 [20:20]

The fourth example involves a bus of length 8 meters traveling at 72 km/h (20 m/s) and approaching an intersection 42 meters away. The light turns yellow, and the driver has 3 seconds before it turns red. The problem presents two options: maintain the current speed or brake with a deceleration of -5 m/s². The video analyzes both options to determine which one allows the driver to avoid violating traffic laws, concluding that maintaining the current speed is the safer option.

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Date: 5/2/2026 Source: www.youtube.com
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